3q^2-118.5q-328.5q=0

Solution for 3q^2-118.5q-328.5q=0 equation:

3q^2-118.5q-328.5q=0

We add all the numbers together, and all the variables

3q^2-447q=0

a = 3; b = -447; c = 0;
Δ = b2-4ac
Δ = -4472-4·3·0
Δ = 199809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{199809}=447$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-447)-447}{2*3}=\frac{0}{6}
=0
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-447)+447}{2*3}=\frac{894}{6}
=149
$